I h2e no i2a w5r a4e is g3g to be a2e to r2d t2s, b1t it m3t w2k.
If n5g e2e it m3t p3e s7g a3t t1e r8y i6t in t1e E5h l6e.
If s5e d2s c3k it, I s3l p2t an e9n.
A l4e t2t.
Comments
9 responses to “A l4e t2t.”
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re: A l4e t2t.
T1e s3y t3g is, I c1n s3t-r2d it.
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re: A l4e t2t.
I have no idea whether anyone is going to be able to read this, but it might work.
If nothing else it must prove something about the redunancy inherent in the English language.
If someone does crack it, i shall post an explaination.
(My spelling sucks, but hopefully you get the idea 😉 )
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re: A l4e t2t.
f3t s6e in g4n: “i1h h2e k2n A4g ob j6n d1s l3n w4n k4n a2r es k2n k5n”
a1d n1w in f4h: “je n ai a4e i2e si q4u’un p4a l2e ca, m2s ca p2t m5r”
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re: A l4e t2t.
a1d a o1e w1y t7r in p2l perl -n -e ‘for $w2d (split) {$w2d =~ s/(.)(.*)(.)/$2/g;$f3t=$1;$l2t=$3;$c3t = $w2d =~ s/./$1/g;print “$f3t$c3t$l2t “;}’
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re: A l4e t2t.
f3t s6e in g4n: “i1h h2e k2n A4g ob j6n d1s l3n w4n k4n a2r es k2n k5n”
a1d n1w in f4h: “je n ai a4e i2e si q4u’un p4a l2e ca, m2s ca p2t m5r”
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re: A l4e t2t.
N1w t2s is s5.
I a6y s5d t2t f3t o1e w1s G4n .
B1t I h4y s3k G4n !
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re: A l4e t2t.
o2s, t2o, t2t l2t o1e s4d be “s3y”.
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re: A l4e t2t.
[)4/\/\1T, w3 d0n4 n336 a ne\/\/ \/\/ /\y 40 w41t3 i14y
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re: A l4e t2t.
0N3 15 B1li|\|GU@l 4Nd C@N 4l50 5P3@K ‘L33T 88888-) w00t!!!
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